Minimum tree - hdu4966
https://vjudge.net/contest/311526#problem/G
General idea: given n(50) attributes, each attribute has a[i](500) level, a n d there are M(2000) courses. To participate in j course, c attribute should reach D.
In this way, you can upgrade your e attribute to f, and spend g yuan at the same time. Ask h ...
Posted by pradee on Tue, 22 Oct 2019 13:26:18 -0700
Vue-CLI3.0 project construction process Series IV: axios application in the project
Now let's talk about the request method in the project - axios
Insert (from netizen): storage token suggests state+localStorageBecause state is a single page, you don't need to log in to open the second web page for the same browser, so you need to use cookies or localstorage. Why not use cookies: 1 ...
Posted by rortelli on Tue, 22 Oct 2019 09:59:20 -0700
Flutter EasyRefresh+ListView+Scoped Model realizes pull-up refresh and paging load
Preface:
The Flutter project needs to realize the function of "pull-up refresh and page loading". The page can divide a large amount of data into small segments and load them in batches. This can effectively avoid the problem that the client slows down due to loading all the data at one time. Here I use the EasyRefresh third-party pl ...
Posted by blade_922 on Tue, 22 Oct 2019 08:08:51 -0700
Server out of band management
In daily operation and maintenance, we may receive the equipment handed over by others, but for many reasons, the previous people did not record the relevant server serial number, unset out of band address and user password of out of band management, etc., and the server cannot be shut down for maintenance. Is there any way to obtain relevant ...
Posted by sunnyvatsal on Tue, 22 Oct 2019 00:27:24 -0700
Simple implementation of Aurora push in Android
Configuration of Aurora push environment for Android
Register APP KEY
Android Studio configuration
Register APP KEY
First of all, we register for the account on the official website of Aurora push to enter the developer service.
Click to create app
The second step:
Define the name of the applica ...
Posted by Xanthis on Mon, 21 Oct 2019 10:22:43 -0700
JAVA CAS single sign on 3: CAS agent model drill
Preface
JAVA CAS single sign on one: build CAS server
JAVA CAS single sign on II: CAS common mode 1 drill
The agent mode is more complex than the normal mode in the previous section. But the configuration will be slightly different. The so-called difficult will not, will not be difficult. If you encounter a problem that you have never met be ...
Posted by lenhewitt on Sun, 20 Oct 2019 22:51:11 -0700
Android--demo collection -- integrated speech recognition (using native speech recognizer)
SpeechRecognizer is located in the android.speech package of the source code (API 29--Android 9.0). Here is a simple call to Demo about the native class. So that you are not familiar with the feasibility of this kind of rapid verification technology.
Tips: 1.SpeechRecognizer will connect to the s ...
Posted by manny on Sun, 20 Oct 2019 15:16:45 -0700
Sword finger offer: merging two sorted linked lists
1. Problem description
Input two monotonically increasing linked lists, and output two synthesized linked lists. Of course, we need the synthesized linked lists to meet the monotone rule.
2. way of thinking
Method 1: non recursive method
According to the problem, which is very similar to the sorting out process, two arrays are sorted separatel ...
Posted by imderek on Sun, 20 Oct 2019 14:46:53 -0700
A comprehensive note about Android getting operators
Time of publication: October 20, 2019
Content overview
This article will give the methods of getting operators on Android, the differences of several similar methods, and the effective ways of getting operators in the case of multiple cards. Finally, a method that does not need to request the device identification code to obtain the operator in ...
Posted by The Wise One on Sun, 20 Oct 2019 04:17:25 -0700
Magic ball problem
Take the bead as the point, if the condition is satisfied, two sides are connected.
So you can find the maximum number of nodes that can be covered by n paths.
As we all know, minimum edge coverage = total number of points - Maximum Matching
Not here Link
So split the points and run the bipartite chart.
It'S about S to x.
The k-direction x 'con ...
Posted by allaboutthekick on Sat, 19 Oct 2019 14:59:20 -0700