For automated test cases, if 100 interfaces are to write 100 sheet forms in Excel, each interface has 10 fields, and 5 of them may be changing, you need to use parameterization, try using specific characters to position first, and replace placeholders when constructing parameters;

1. Replace the mobile phone number by using replace in the string

# Original string:{"mobilephone": "${not_existed_tel}", "pwd":"123456"}
# json Character string
src_str = '{"mobilephone": "${not_existed_tel}", "pwd":"123456"}'
# replace json In string ${not_existed_tel} 18845820369
print(src_str.replace("${not_existed_tel}", "18845820369"))

# Result:{"mobilephone": "18845820369", "pwd":"123456"}

2. Replace with re module

re regular expression is a formatting language for finding, searching, and replacing text

Search method one, match method in re module, match method is match from scratch

import re


# 1. Create original string(String to replace)
src_str4 = '{"mobilephone": "${not_existed_tel}", "pwd":"123456"}'

# 2. Define pattern strings to match
# Pattern string == Mod, use this template to compare in the original string

# Method One, re Regular match(Translate: March) Method, match The method is to match from scratch
# from { Start, don't match, Then reply None
res = re.match("{not_existed_tel}", src_str4)
print(res)  # Result: None

# from { Start, match up, Will return Match Object, plus r No escape required
res = re.match(r'{"mobilephone"', src_str4)
print(res)      # Return Match Object Result:<re.Match object; span=(0, 14), match='{"mobilephone"'>

# Get matching result content group (Translate: Songs are broken)
a = res.group()
print(a)        # Result:{"mobilephone"

search Method 2: search method, matching only once

import re


# 1. Create original string(String to replace)
src_str1 = '{"mobilephone": "${not_existed_tel}", "pwd":"123456"}'

# 2. Define pattern strings to match
# Pattern string == Mod, use this template to compare in the original string:"${not_existed_tel}"

# Method 2: search (Astringent) Method, match only once
# Return if match Match object,Unmatched will not return None
# Dollar sign needs escaping plus r，Escape is required for special characters
res1 = re.search(r"\${not_existed_tel}", src_str1)
print(res1)     # Match Object Result:<re.Match object; span=(17, 35), match='${not_existed_tel}'>

# Get matched results, group(Method
b = res1.group()
print(b)    # Result: ${not_existed_tel}

Search method three: findall method, which matches many times

src_str1 = '{"mobilephone": "${not_existed_tel}", "pwd":"123456"}'
res2 = re.findall(r'o', src_str1)
print(res2)     # Return list results directly:['o', 'o', 'o']

Replace method: sub method

import re


# 1. Create original string(String to replace)
src_str2 = '{"mobilephone": "${not_existed_tel}", "pwd":"123456"}'

# The first parameter is the pattern string: ${not_existed_tel}
# The second parameter is the new string: 18845820369
# The third parameter is the original string
# sub Method if it matches, Then the replaced string is returned
# sub Method if not matched, Then return the original string directly

# Use search Method searches first, searches then uses sub Method to replace; count=0 Default Match Once
if re.search(r"\${not_existed_tel}", src_str2):     # Search first
    res2 = re.sub(r"\${not_existed_tel}", "18845820369", src_str2)  # In Replacement
    print(res2)
else:
    print("Unable to match original string")
# Replacement results:{"mobilephone": "18845820369", "pwd":"123456"}

# Use regular matching:\w+ Word Characters[A-Za-z0-9_]，+ Match multiple times; match in the original string by regular
if re.search(r"\${\w+}", src_str2):     # Search first
    res2 = re.sub(r"\${not_existed_tel}", "18845820369", src_str2)  # In Replacement
    print(res2)
else:
    print("Unable to match original string")
# Replacement results:{"mobilephone": "18845820369", "pwd":"123456"}

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