Summary -- several methods of generating unique id in JS

Keywords: Front-end network less

Occasionally in development, when it is necessary to generate a unique id, such as adding, deleting or modifying any item of the array many times, it is necessary to add a unique identifier to each item to distinguish. The following are various methods of generating unique identification collected from the network, which are summarized here for future reference.

Method 1

function uuid() {
    var s = [];
    var hexDigits = "0123456789abcdef";
    for (var i = 0; i < 36; i++) {
        s[i] = hexDigits.substr(Math.floor(Math.random() * 0x10), 1);
    }
    s[14] = "4"; // bits 12-15 of the time_hi_and_version field to 0010
    s[19] = hexDigits.substr((s[19] & 0x3) | 0x8, 1); // bits 6-7 of the clock_seq_hi_and_reserved to 01
    s[8] = s[13] = s[18] = s[23] = "-";
 
    var uuid = s.join("");
    return uuid;
}

Method 2

function guid() {
    return 'xxxxxxxx-xxxx-4xxx-yxxx-xxxxxxxxxxxx'.replace(/[xy]/g, function (c) {
        var r = Math.random() * 16 | 0,
            v = c == 'x' ? r : (r & 0x3 | 0x8);
        return v.toString(16);
    });
}

Method 3

 

function guid2() {
    function S4() {
        return (((1 + Math.random()) * 0x10000) | 0).toString(16).substring(1);
    }
    return (S4() + S4() + "-" + S4() + "-" + S4() + "-" + S4() + "-" + S4() + S4() + S4());
}

Method 4

 

/*
    Specify length and base
*/
function uuid2(len, radix) {
    var chars = '0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz'.split('');
    var uuid = [],
        i;
    radix = radix || chars.length;
 
    if (len) {
        // Compact form
        for (i = 0; i < len; i++) uuid[i] = chars[0 | Math.random() * radix];
    } else {
        // rfc4122, version 4 form
        var r;
 
        // rfc4122 requires these characters
        uuid[8] = uuid[13] = uuid[18] = uuid[23] = '-';
        uuid[14] = '4';
 
        // Fill in random data.  At i==19 set the high bits of clock sequence as
        // per rfc4122, sec. 4.1.5
        for (i = 0; i < 36; i++) {
            if (!uuid[i]) {
                r = 0 | Math.random() * 16;
                uuid[i] = chars[(i == 19) ? (r & 0x3) | 0x8 : r];
            }
        }
    }
 
    return uuid.join('');
}

Originally thought that the core of such methods should be to use New Date() to generate a unique random number, but it didn't work.. In addition, I temporarily used the second method, yes, less code.

Posted by fesan on Fri, 24 Apr 2020 07:13:11 -0700