LeetCode brush notes linked list traversal linked list
160 intersecting linked list
Given two linked lists, judge whether they intersect at a point, and find the intersection node.
The input is two linked lists and the output is one node. If there are no intersecting nodes, an empty node is returned.
Input: intersectVal = 8, listA = [4,1,8,4,5], listB = [5,0,1,8,4,5], skipA = 2, skipB = 3 Out ...
Posted by suvarthi on Wed, 10 Nov 2021 19:12:06 -0800
[UE4 C + +] octree implementation and visualization
preface
Implementation version of this article: 4.26
See the end for reference
Article address https://www.cnblogs.com/shiroe/p/15534304.html
concept
definition
Octree (English: octree) is a tree data structure. Each internal node has exactly eight child nodes. Octree is often used to segment three-dimensional space and recursively subdivi ...
Posted by Chris_Evans on Wed, 10 Nov 2021 18:01:51 -0800
Multi school sprint NOIP simulation 27 - Super doubling - reconstruction tree
No link is provided for this question
Title Description
Given a tree. We think one
x
→
y
x\rightarrow y
Simple path of x → y(
x
≠
...
Posted by phpnewbie911 on Wed, 10 Nov 2021 08:11:15 -0800
Judge whether it is a balanced binary tree - js
01 - sum of two numbers - js
describe Given an integer array numbers and a target value target, please find two subscripts in the array that add up to the target value, and the returned subscripts are arranged in ascending order.
Example 1
Input:[3,2,4],6
Return value:[2,3]
Note: because 2+4=6 ,And the subscript of 2 is 2, and the subscrip ...
Posted by sherri on Wed, 10 Nov 2021 08:05:06 -0800
list_files and tuple_regexp_select function
#Get image
read_image(Image,'E:/C/Halcon/1.jpg')
#Read images of the entire folder
#1 list the files in the specified path
list_files('E:/C/Halcon',['files','follow_links'],ImageFiles)
#2. Select qualified documents
tuple_regexp_select(ImageFiles,['\\.(tif|tiff|gif|bmp|jpg|jpeg|jp2|png|pcx|pgm|ppm|pbm|xwd|ima|hobj)$','ignore_case'],ImageFiles)
...
Posted by plezops on Wed, 10 Nov 2021 07:13:45 -0800
Learning notes: tree chain subdivision
preface
Tree chain subdivision divides the edges of the tree into many chains, so as to reduce the complexity of modifying queries on the tree. This is an introduction to light and heavy chain segmentation. Concept: Heavy son: the son with the most nodes in the subtree. If the subtrees of two sons are the same, then any one of them. Light son: ...
Posted by FuriousIrishman on Wed, 10 Nov 2021 05:51:17 -0800
On the hierarchical traversal of binary tree and the extension of written test questions (data structure)
1, Hierarchical traversal of binary tree
It is unrealistic to traverse directly, because there are more nodes in the future, and not all nodes in each layer are 2k-1. If you traverse a node, save the child of the node and get it from the structure next time. Here, the child is saved in a queue (the node first placed in the space is ...
Posted by jwcsk8r on Tue, 09 Nov 2021 11:38:05 -0800
Niuke challenge 48 E Speed Forwarding (tree over tree)
Link: E-speed forwarding_ Niuke challenge 48 (nowcoder.com)
The given length is
n
n
Sequence of n
a
a
a. Altogether
m
...
Posted by somenoise on Tue, 09 Nov 2021 03:55:05 -0800
Persistent segment tree
Before talking about the persistent segment tree, you need to know what the segment tree is. If you still don't know the segment tree, you can take a look at the template I wrote about the segment tree and attach the blog address here: (63 messages) segment tree template_ AC__dream blog - CSDN blog
We know that the segment tree supports modifi ...
Posted by jpraj on Tue, 09 Nov 2021 00:19:11 -0800
Task2 Python basic exercise: data structure summary
Task 2 Python basics review: data structure summary
List list
1. Create a list by derivation
x = [i for i in range(100) if (i % 2) != 0 and (i % 3) == 0]
#[3, 9, 15, 21, 27, 33, 39, 45, 51
#, 57, 63, 69, 75, 81, 87, 93, 99] <class 'list'>
2. Since the element of the list can be any object, what is saved in the list is the pointer of ...
Posted by tyler on Mon, 08 Nov 2021 16:26:26 -0800