js function exercises

1. Number related to 7 within output 100

function num(a){
			for(var i=1;i<=100;i++){
			 	if (i%a==0||parseInt(i/10)==a||(i%10)==a) {
			 		document.write(i+'<br>');
			 	}
			}
		}

num(7);

2. Output all numbers from 1 to 100 that cannot be divided by 3; and output the sum of these integers

function show(b){
			var sum=0;
		 for(var i=1;i<=100;i++){
		 	if (i!=(i%b==0)){
		 		sum+=i;
		 	}
		 }
		 console.log('As for'+sum);
		}

show(3);

3. Make a small game, report the safety number of Game 7 (report in turn, report can be divided by 7 or the ending number is 7, perform the program), report the safety number between 1-100

function game(c){
		for(var i=1;i<=100;i++){
		 	if (i%c==0||(i%10)==c) {
		 		
		 		continue;
		 	}
		 	document.write(i+'<br>');
		 }
}

game(7);

4. Print the number of daffodils (three digits), (153 = 1111 + 555 + 33 * 3) the sum of the cubes of each digit is equal to the number, that is, the number of daffodils, and print out all the number of daffodils.

function sum(i){
			for(var i=100;i<1000;i++){
		 	var a=i%10;
		 	var b=(i%100-a)/10;
		 	var c=parseInt(i/100);
		 	num=c*c*c+b*b*b+a*a*a;
		 	if (i==num) {
		 		document.write(i+'<br>');
		 	}
		 }
		}

		sum();

5. Find the factorial of 10

function sum(i){
			var sum=1;
		 for(var i=1;i<=10;i++){
		 	sum*=i;
		 }
		 document.write(sum);
		}

		sum(10);

6. Everest is 8848 meters above sea level. Now there is enough paper with a thickness of 0.01 meters. How many times can it be folded higher than Everest.

function num(height){
			var count=0;//Statistics times
			var totalHeight=884800;//Altitude
			while(height<=totalHeight){
				height*=2;
				count++;//Counter change
				//if (height>=totalHeight) {
				//break;
				//}
			}
			return count;
}

	var count=num(1);
	console.log('Fold'+count+'second');

7. Print the following figure

	// *
	// ***
	// *****
	// *******
	// *********
function yao(i){
			for(var i=1;i<5;i++){
			//Output one line*
			for(var j=1;j<=2*i-1;j++){
				document.write('*');
			}
			document.write('<br>');
			}
		}

		yao(5);

Posted by mahendrakalkura on Wed, 20 Nov 2019 09:27:09 -0800