1. Basic questions

1. Print pass or fail according to the range of grades entered

score = int(input('Enter grade:'))
if score >= 60:
    print('pass')
else:
    print('fail,')

1. Print adults or minors according to the entered age range. If the age is not within the normal range (0 ~ 150), it is not a person!.

age = int(input('Enter age:'))
if 0 <= age <= 150:
    if age >= 18:
        print('adult')
    else:
        print('under age')
else:
    print('This is not a person!')

1. Enter two integers a and b. if the result of a-b is odd, the result will be output. Otherwise, the result of output prompt information a-b is not odd.

a = int(input('input a: '))
b = int(input('input b: '))
if (a-b) % 2 == 0:
    print('a-b The result is not odd')
else:
    print(a-b)

1. Enter the year. If the entered year is a leap year, print 'leap year', otherwise print 'normal year'

year = int(input('Enter year:'))
result_1 = (year % 4 == 0 and year % 10 != 0) or year % 400 == 0
if result_1:
    print('leap year')
else:
    print('Ordinary year')

1. Use the for loop to output multiples of all 3 in 0 ~ 100.

for i in range(0, 101, 3):
    print(i)

1. Use the for loop to output the number of single digits or tens within 100 ~ 200 that can be divided by 3.

for i in range(100, 200):
    num = i // 10 % 10
    num_1 = i % 10
    if num % 3 == 0 or num_1 % 3 == 0:
        print(i)

1. Count the number of tens in 100 ~ 200 that are 5

for i in range(100, 200):
    num = i % 10
    if num % 10 == 5:
        print(i)

1. Print all numbers in 50 ~ 150 that can be divided by 3 but cannot be divided by 5

for i in range(50, 150):
    if i % 3 == 0 and i % 5 != 0:
        print(i)

1. Calculate the sum of all numbers in 50 ~ 150 that can be divided by 3 but cannot be divided by 5

sum_1 = 0
for i in range(50, 150):
    if i % 3 == 0 and i % 5 != 0:
        sum_1 += i
print(sum_1)

2. Advanced questions

1. Use the cycle to calculate the result of 1 * 2 * 3 * 4 *... * 10.

sum_1 = 1
for i in range(1, 11):
    sum_1 *= i
print(sum_1)

1. Count the number of digits within 100 that are 2 and can be divided by 3.

count = 0
for i in range(1, 101):
    if i % 3 == 0 and i % 10 == 2:
        count += 1
print(count)

1. Enter any positive integer and find how many digits it is?

Note: you can't use strings here. You can only use loops

num = int(input('Enter a positive integer:'))
count = 0
while num // 10 != 0:
    count += 1
    num = num // 10
else:
    count += 1
print(count)

1. Print out all the numbers of daffodils. The so-called daffodils number refers to a three digit number, and the square sum of each digit is equal to the number itself. For example: 153 yes

   The number of fairy flowers is 1 ³ + five ³ + three ³ Equals 153.

   for i in range(100, 1000):
       x = i % 10
       y = i % 100 // 10
       z = i % 1000 // 100
       if x**3 + y**3 + z**3 == i:
           print(i)
   

3. Challenges

1. Judge whether the specified number is a prime number (a prime number is a prime number, that is, a number that cannot be divided by other numbers except 1 and itself)

num = int(input('Please enter a number:'))
if num % 2 != 0 and num % 3 != 0:
    print('It's a prime')
else:
    print('Not prime')

1. Find the value of the nth number in the Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34... (here n can be any positive integer, which can be determined by input)

n = int(input('Enter number n: '))
if n <= 2:
    print(1)
else:
    num_1 = 1
    num_2 = 1
    for i in range(n - 2):
        num = num_1 + num_2
        num_2 = num_1
        num_1 = num
print(num)

1. Output 9 * 9 formula. Procedure analysis: Considering branches and columns, there are 9 rows and 9 columns in total, i control row and j control column.

for i in range(1, 10):
    for j in range(1, 10):
        print(i, '*', j, '=', i*j, end=' ', sep='')
    print('')

1. This is the classic question of "100 horses and 100 loads". There are 100 horses, carrying 100 loads of goods, 3 loads of horses, 2 loads of medium horses and 1 load of two ponies. How many are the big, medium and small horses? (exhaustive method can be used directly)

for a in range(34):
    for b in range(100 - a):
        if a * 3 + b * 2 + (100 - a - b) / 2 == 100:
            print('Malaysia has', a, 'Horse', 'Zhongma you', b, 'Horse', 'Pony has', 100-a-b, 'Horse', sep='')